Each sector is of 64 K.
1 KB = 1024 byte
Lets say the starting address is 0x016F2818 and you have reserved 192 sectors for this , so what will be end address ?
1) Convert in decimal all numbers
1024*64*192 ===12582912, convert in hexa = c00000
2) Now add to starting location address
016f2818+c00000=22f2818
3) The end address will be 22f2818-1 =0x22f2817
